2025 WAEC Further Maths Answers Posted 7:00am

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2025 WAEC FURTHER MATHS ANSWERS

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*FURTHER MATHEMATICS ANSWERS*
*INSTRUCTIONS; YOU ARE ANSWER ALL QUESTIONS IN* *SECTION (A)AND ANSWER ONLY FOUR QUESTIONS IN SECTION (B)*
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NUMBER 1,2,3,4,5,6,7,8,9,10,11,13,14 POSTED

Examkey Waec Answers 2025 Expo Runz

FURTHER MATHEMATICS-OBJ

1-10: BBCCCDDCAB

11-20: BBBBBADDBA

21-30: CCCDCBDBAA

31-40: ACDDADDDBD

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Completed.

NO. 1

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NO. 2[br]

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NO. 3[br]

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NO. 4[br]

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NO. 5[br]

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NO. 6[br]

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NO. 7[br]

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NO. 8[br]

(8)[br]
To find MP, we can use the fact that P is the midpoint of NO. Since P is equidistant from MN and MO, the line segment MP is the perpendicular bisector of NO.[br]

First, let’s find the coordinates of P. The midpoint of NO can be calculated by taking the average of the corresponding coordinates of N and O:[br]

P = (1/2)(N + O)[br]

Given MN = 8i + 3j and MO = 14i – 5, we can find the coordinates of N and O:[br]

N = (8i + 3j) + (14i – 5) = 22i – 2 + 3j[br]
O = (14i – 5) + (8i + 3j) = 22i – 2 + 3j

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Now, we can find P:[br]

P = (1/2)((22i – 2 + 3j) + (22i – 2 + 3j))[br]
= 1/2(44i – 4 + 6j)[br]
= 22i – 2 + 3j

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Next, we can find the vector MP by subtracting the coordinates of M from the coordinates of P:[br]

MP = P – M[br]
= (22i – 2 + 3j) – (14i – 5)[br]
= 8i + 3j + 3[br]

Therefore, MP = 8i + 3j + 3.

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NO. 9[br]